Azuma Hashimoto (azuma_h@hotmail.com) Thu, 07 Dec 2000 11:37:56 -0800
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From: "Azuma Hashimoto" <azuma_h@hotmail.com> Subject: address decoders Date: Thu, 07 Dec 2000 11:37:56 -0800Hi. I have a question about exercise 7 from the microcomputer architecture handout. In it we are supposed to draw out a diagram for a microcomputer. But when you did it in class the address decoder only gets an 18 bit address? Why is that? Is it because the I/O chip could always potentially be active with any other activity? So that when you have the EPROM and I/O active at the same time the address decoder needs 16(for EPROM) + 2(for I/O) = 18 bits????? _____________________________________________________________________________________ Get more from the Web. FREE MSN Explorer download : http://explorer.msn.com
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