Re: 5.26 & 6.11

sergio gonzalez (sergiog@ece.ubc.ca) Wed, 23 Feb 2000 09:31:46 -0800 (PST) 

Date: Wed, 23 Feb 2000 09:31:46 -0800 (PST)
From: sergio gonzalez <sergiog@ece.ubc.ca>
Subject: Re: 5.26 & 6.11



Hello,

For Q5.26, assume alpha=1, so that gamma will just equal Eb/No. I
discussed this with Dr. Casas already, and confirmed that the assumption
was OK after sepending some time playing around with the equations. It's
still kind of confusing though.

For Q6.11, I thought of doing the same thing, which is, 'reversing' the Q
function, but I'm not sure whether this approach is OK because I believe
the eq. for the Q function only works for the AWGN channel, which is not
faded. I'm really not sure. 


On Tue, 22 Feb 2000, Maria Lei [4681] wrote:

> Hi,
> 
> Does anyone know the answers for the followings:
> 
> Q5.26:
> a) I use fig5.53 to find the corresponding Eb/No.  Then from eqn 5.157, I 
>    can obtain alpha^2 (mean)
> 
> b) from part a), I have already obtained alpha^2 (mean).  Therefore, I 
>    use equation from ex5.12 to obtain Eb/No for a Ricean fading channel.
>   
> Is this approach correct?  
> 
> Q6.11:
> c) How to find P-1(x)?  Is P(x) the Q function for BPSK?  or does P(x)
> refers to eqn 5.155?  
> 
> Regards,
> Maria
> 
>