ELEX 4653 Lab 1

This lab provides practice defining scalar and container values.

April 25, 2022.

Instructions:

• Modify this notebook by adding the Python code described below.

• Test your code using the menu item Cell ► Run All

• Save the notebook (the .ipynb file) and upload it to the appropriate Assignment folder on the course web site.

Question 1

Create the following variables:

• a string variable named myid that is your BCIT ID. For example "A00123456".
• an integer equal to the second-last digit of your ID
• a float equal to the ratio of the last two digits (as computed by division)
• a string equal to the first three characters of myid
• a bool that is True if the last digit is even and False if it is odd
• a complex whose real part is the second-last digit and whose imaginary part is the last digit

For example, if your BCIT ID were A00123456 then myid would equal "A00123456" and mylist would equal [6, 0.8333.., 'A00', True, 5+6j]

If the last digit of your student number is 0, replace it with a 1. For example, if you student number is A00123450, set myid to "A00123451".

myid="A00123458"
mylist=[5, 5/8, "A00", True, float(myid[7])+float(myid[8])*1j]
myid,mylist

('A00123458', [5, 0.625, 'A00', True, (5+8j)])

# this code prints some variables that you will need to use in your solution
# do not modify this code!
import random
import math
if 'myid' not in locals():
    print("myid not defined.")
else:
    random.seed(int(myid[1:]))
    labels=[]
    k=random.randrange(4,5)
    while len(labels)!=k:
        digits=random.choices(list(range(10)),k=k)
        labels=list(set([''.join(random.choices('ABCDXYZLMNP'+'0123456789',k=random.randrange(3,5))) 
                for i in range(k)]))
    print(f"labels={labels}\ndigits={digits}")

labels=['P3M', 'CLB8', 'AMZB', '67NY']
digits=[1, 9, 7, 1]

Question 2

Create a dict named mydict where the keys are the strings in labels and the values are the digits from digits. For example, if:

labels=['6P05', '780C', 'BA8', 'ADBP'] and

digits=[0, 1, 0, 6] then

mydict would be { '6P05':0, '780C': 1, 'BA8': 0, 'ADBP':6 }.

mydict=dict(zip(labels,digits))
print(mydict)    

{'P3M': 1, 'CLB8': 9, 'AMZB': 7, '67NY': 1}

Question 3

Create a set called odds containing all of the odd values in digits. For example if digits is [0,1,3,3,4,5] then odds would be set to {1,3,5}.

odds=set([i for i in digits if i%2==1])
digits,odds

([1, 9, 7, 1], {1, 7, 9})

# lab validation code; do not modify
def labcheck():
    import copy, re

    def q1():
        b,a = [int(v) for v in myid[-2:]]
        assert type(myid) == str and len(myid) == 9 and \
            [int(myid[7]), b/a, myid[:3], not a%2, b+a*1j] == mylist, \
            f"mylist = {mylist} for myid = {myid}"
        
    def q2():
        assert (type(mydict) == dict and
            sorted(mydict.keys()) == sorted(labels) and
            all([mydict[a] == b for a,b in zip(mydict.keys(), mydict.values())])), \
            f"mydict = {mydict}"
    
    def q3():
        assert ( type(odds) == set and 
            all((i in odds for i in digits if i%2)) and not 
            any((i not in digits for i in odds))), \
            f"odds = {odds} for digits = {digits}"
    
    for s,i in [(s,s[1:]) for s in locals().keys() if re.search(r'q\d+',s)]:
        try:
            locals()[s]()
            print(f"Question {i} OK.")
        except Exception as e:
            print(f"Failed check for Question {i}: {e}")
            
labcheck()

Question 1 OK.
Question 2 OK.
Question 3 OK.