Final Exam Marking Scheme
			 BCIT ELEX 3525
			    Fall 2013

Marks were assigned for each questions as described below.

Question 1 (out of 7)

- number of characters encoded (2): 1
- convert each byte to binary (1100 1110, 1001 0001): 1
- look up bit pattern in table (from 2nd line): 1
- extract the right bits (5 x bits and 6 y bits): 1
- combine into right binary/hex codepoint values(0x391): 1
- convert *combined* values to decimal(913): 1
- correct answer for second value (add 1 to above): 1

[if tried to encode as 4 glyphs or if treated the bytes as two
code points (codepoint to UTF-8; reverse of required conversion)
only awarded 1/7 (for the conversion to binary, if done
correctly)]

Question 2 (out of 4)

- using Friis equation: 1
- convert each of given values to dB and dBm(if necessary): 1
- compute wavelength(0.05m): 1
- get right answer(-60dBm,1E-6mW,1E-9W): 1

[many people did not convert distance from km to meters]


Question 3 (out of 5)

- convert to binary: 1
- right bit order: 1
- right data polarity: 1
- right start and stop bit polarity: 1
- labelled x and y axis: 1

Question 4 (out of 2)

- Shannon capacity equation: 1
- right answer(500kb/s): 1

Question 5 (out of 4)

- signal voltages(+/-2V): 1
- correctly compute noise standard deviation(sigma=1): 1
- correct value of t or argument to erfc(-2): 1
- right answer(2 or 3%): 1

Question 6 (out of 2)

- used differential decoding: 1
- right answer(1101): 1

[a correct answer was sufficient]

Question 7 (out of 12)

(a) answer(no - 3kHz not present in input, yes - 3kHz is an IMD product: 2x2-1): 1, explanation: 1
(b) answer(8000 symbols/second): 1, bandwidth x 2: 1
(c) answer(random): 1
(d) answer (WiFi,IP,UDP,HTTP): 2; -1 for each protocol in wrong order
(e) answer(yes, same OUI): 1
(f) answer(0xFFF0): 1; computation method: 1
(g) answer(yes): 1, computation using a netmask: 1